The mass of Hydrogen in 92 g of CH4O is 11.5 grams
Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements
In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison
With this law, we can calculate how many grams an element is needed to make a compound with a certain mass, as desired
The mass of compounding compounds can also be calculated.
For example, the mass ratio of oxygen (O) and hydrogen (H) elements in H₂O remains at 8: 1. So if you know the amount of mass of oxygen you can know the amount of hydrogen and water mass.
Or the comparison of CO₂ with C: O = 3: 8
Mass A in AxBy = (x x Ar A x mass AₓBy) / Mr AₓBy
Mass B in AₓBy = (y x Ar B x mass AₓBy) / Mr AₓBy
Note that x, y are the numbers of A and B in AₓBₐ
In CH₄O compounds (Methanol, with relative molecular mass = 32) has a mass of 92 grams and there are 4 Hydrogen atoms, so the mass is:
[tex]mass~H~=~\frac{(4\times relative~atomic~mass~H}{relative~molecular~mass ~CH_4O}~\times~mass~CH_4O[/tex]
[tex]mass~H~=~\frac{4\times1}{32} \times~92[/tex]
mass H = 11.5 grams
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Keywords: Proust, the Comparative Law, CH₄O
