Ellen has card with geometric figures on them. She has 2 cards with a circle, 1 card with a square, and 1 card with a triangle. She selects a card twice, with replacement. She plans to do this 120 times. Which is a reasonable prediction for the number of times she will select the same figure twice?

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Answer:

To solve this problem, we can calculate the probability of selecting the same figure twice on each pair of selections and then multiply it by the total number of pairs (120).

The probability of selecting the same figure twice in one pair is the sum of the probabilities of selecting a circle twice, a square twice, or a triangle twice.

- Probability of selecting a circle twice = (2/4) * (2/4) = 1/4 * 1/4 = 1/16

- Probability of selecting a square twice = (1/4) * (1/4) = 1/16

- Probability of selecting a triangle twice = (1/4) * (1/4) = 1/16

So, the total probability of selecting the same figure twice in one pair is 1/16 + 1/16 + 1/16 = 3/16.

Now, to find the expected number of times she will select the same figure twice in 120 pairs, we multiply the probability by the total number of pairs:

Expected number = 3/16 * 120 = 22.5

Since you can't have half of a selection, the most reasonable prediction is that she will select the same figure twice approximately 22 times.

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