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There are 4 red balls, 6 white balls, and 3 blue balls in a bag. If one ball is drawn from the bag at random, what is the probability that it is not white?
a. 1/7
b. 5/6
c. 7/13
d. 1/13

Respuesta :

First you want to add all the numbers up.  Then you have to subtract from the amount of white balls (which will give you seven).  Put 7 above the sum of all the balls and so the chances of getting a ball that is not white would be 7/13.
Benjamin16
[tex]P'(A) = \frac{6}{4+6+3}= \frac{6}{13} \\ \\ P(A) = 1-P'(A) \\ \\ P(A)=1- \frac{6}{13}= \frac{7}{13} [/tex]

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