Respuesta :
Answer:
[tex]E=4.68\times 10^{-19}\ J[/tex]
Explanation:
It is given that,
Frequency of shade of blue, [tex]f=7.07\times 10^{14}\ Hz[/tex]
Let E is the energy of exactly one photon of this light. The relationship between the energy and the frequency is given by :
[tex]E=h\times f[/tex]
h is the Planck's constant
[tex]E=6.63\times 10^{-34}\times 7.07\times 10^{14}[/tex]
[tex]E=4.68\times 10^{-19}\ J[/tex]
So, the energy of exactly one photon of this light is [tex]4.68\times 10^{-19}\ J[/tex]. Hence, this is the required solution.
