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Punnett square are used to show possible combinations of alleles or to predict the probability of a trait occurring in offspring. A pansy that is homozygous for purple flowers (PP) is crossed with a pansy that is homozygous for pink flowers (pp). Which genotypes will be included for the offspring in the Punnett square for this cross?

Respuesta :

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When we cross PP x pp we obtain:

Pp + Pp + Pp + Pp (we obtain four identical genotype).

Pp (heterozygote flower) is the Only genotype when we cross two different homozygotes.

The phenotype will be the purple flower since it is the dominant genotype.

Answer:

The correct answer would be Pp.

The genotype of one parent is PP. Thus, it will produce only one type of allele, that is, P.

Similarly, the genotype of another parent is pp. Thus, it will produce only one type of gamete, that is, p.

The cross would produce offspring with only one type of genotype, that is, heterozygous Pp.

The phenotype of all the offspring will be purple as it is a dominant trait.

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