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Which absolute value functions will be narrower than the parent function, f(x) = |x|? Check all that apply. f(x) = |x| f(x) = |x – 2| f(x) = |x| + 3 f(x) = 2.9|x| f(x) = 1.2|x + 8| f(x) = 0.7|x| – 3.2

Respuesta :

meerkat18
When you say narrower, it means that the range would be slimmer. Hence, it would be logical to choose the function in which the value of f(x) would decrease. Try substituting values for x to the functions in the choices. If the answer is less than the value of x you chose, then that is the answer. The acceptable answers would be:

f(x) = |x – 2|
f(x) = 0.7|x| – 3.2

The absolute value functions narrower than the parent function are: f(x) = |x| - 3 and f(x) = 0.7|x| - 3.2. This conclusion can be obtained by substituiting any value of x (let x = 2).

Given :

Parent Function - f(x) = |x|

Put any value of x in the parent function and put the same value of x in the absolute value function to determine which absolute value function will be narrower than the parent function.

  • At x = 2, parent function, f(x) = |x| becomes f(x) = |2| = 2

  • At x = 2 absolute value function, f(x) = |x - 2|, becomes f(x) = 0

  • At x = 2 absolute value function, f(x) = |x| - 3, becomes f(x) = -1

  • At x = 2 absolute value function, f(x) = 2.9|x|, becomes f(x) = 5.8

  • At x = 2 absolute value function, f(x) = 1.2|x+8|, becomes f(x) = 12

  • At x = 2 absolute value function, f(x) = 0.7|x| - 3.2, becomes f(x) = -1.8

So, it can be conclude that the absolute value functions narrower than the parent function are: f(x) = |x| - 3 and f(x) = 0.7|x| - 3.2.

For more information, refer the link given below

https://brainly.com/question/23505310

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