Respuesta :
we are given
system of equations as:
[tex] 4x+3y=12 [/tex]
[tex] 2x+3y=-6 [/tex]
Firstly, we can draw graph
we can see that
intersection point lies in quadrant IV
and intersection point is (9,-8)
so, the solution is
x=9 and y=-8 and it is in quadrant IV...........Answer