Answer:
Step-by-step explanation:
Given is a function
[tex]f(x) = x^2 − 5x + 4[/tex]
Let us write in vertex form by completion of squares
[tex]f(x) =x^2-5x+6.25-6.25+4\\=(x-2,5)^2-2.25[/tex]
Leading term is positive. Open upward
Hence minimum at the vertex = (2.5, -2.25)
x intercepts are
[tex]x^2-5x+4\\=(x-4)(x-1)[/tex]
x=4 and 1 are x intercepts
graph of a quadratic function with a minimum at 2.5, negative 2.4 and x-intercepts at 1 and 4
Here we have the quadratic function:
[tex]f(x) = x^2 -5x + 4[/tex]
The vertex of this quadratic equation is at:
x = 5/2 = 2.5
The leading coefficient is positive, so the minimum is at the vertex.
Then we can conclude that the correct option is:
" graph of a quadratic function with a minimum at 2.5, negative 2.4 and x-intercepts at 1 and 4"
If you want to learn more about quadratic functions:
https://brainly.com/question/1214333
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