so the points are (-3/7,-8/3) and (-5/2,-2)
to find the slope do
(y2-y1)/(x2-x1)
(x,y)
x1=-3/7
y1=-8/3
x2=-5/2
y2=-2
subsitute
[tex] \frac{-2-( \frac{-8}{3} )}{ \frac{-5}{2} - \frac{-3}{7} } [/tex]
simplify by finding similar denomenators
[tex] \frac{\frac{-6}{3}-( \frac{-8}{3} )}{ \frac{-35}{14} - \frac{-6}{14} } [/tex]
[tex] \frac{\frac{-6}{3}( \frac{8}{3} )}{ \frac{-35}{14} + \frac{6}{14} } [/tex]
add
[tex] \frac{\frac{2}{3}}{ \frac{-29}{14}} [/tex]
multiply top and bottom by [tex] \frac{-14}{29 [/tex]
[tex] \frac{\frac{-28}{87}}{1} [/tex]
[tex] \frac{-28}{87} [/tex]
answer is
slope=[tex] \frac{-28}{87} [/tex]
