Answer:
8x+6 and 8x-6
C and D are correct.
Step-by-step explanation:
Given: [tex]64x^2-36[/tex]
We need to factor it and choose two polynomial of factored form.
[tex]\Rightarrow 64x^2-36[/tex]
First we write as perfect square each term and difference of square
[tex]\Rightarrow (8x)^2-6^2[/tex]
Because 64 = 8x8 and 36=6x6
Using difference of square identity,
[tex]a^2-b^2=(a+b)(a-b)[/tex]
[tex]\Rightarrow (8x+6)(8x-6)[/tex]
Thus, Two factors are 8x+6 and 8x-6
Two binomial of factors are 8x+6 and 8x-6
