Respuesta :
5.28519s assuming acceleration of gravity is 9.8m/s. When I doubled the length of the pendulum I used 70 since the original was 35.15234.
What is time period of a simple pendulum?
The time period of a simple pendulum is defined as the time taken by the pendulum to finish one full oscillation .
Time period (T) of a simple pendulum = 2π[tex]\sqrt{l/g}[/tex]
given :
Time period (T1) = 3.8 second
L1 = ?
Time period (T1) = 2π[tex]\sqrt{L1/g}[/tex]
3.8 sec = 2 * 3.14 [tex]\sqrt{L1/9.8}[/tex]
squaring both the sides
14.44 = 39.44 * ( L1 / 9.8 )
L1 = 35.16 m
since , the length of the pendulum is doubled
L2 = L1*2 = 35.16 * 2 = 70.32 m
Let the period t of the longer pendulum will be = T2
Time period (T2) = 2π[tex]\sqrt{L2/g}[/tex]
= 2 * 3.14 [tex]\sqrt{70.32/9.8}[/tex]
= 16.83 seconds
The time period t of the longer pendulum will be 16.83 seconds
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