[tex]Answer :P(\text{ Mike's next free throw attempt will go in the basket })= 0.75[/tex]
Explanation:
Since we have given that ,
Total number of free throws Mike has =84
Number of free throws have gone in the basket = 63
As we know that
[tex]P(\text{ Mike's next free throw attempt will go in the basket})= \frac{\text{Number of favourable outcome}}{\text{Total number of outcomes}}[/tex]
[tex]P(\text{ Mike's next free throw attempt will go in the basket })= \frac{63}{84}[/tex]
∴ [tex]P(\text{ Mike's next free throw attempt will go in the basket })= 0.75[/tex]
